[C++] conjunction/disjunction/negation
Updated:
개요
- conjunction
- and 연산을 효과적으로 수행
- disjunction
- or 연산을 효과적으로 수행
- negation
- 부정 연산 수행
예제
- 코드
#include <iostream> using namespace std; template <typename T, typename... Ts> void func(T, Ts...) { if (conjunction<is_same<T, Ts>...>::value) { cout << "conjunction" << endl; } if (disjunction<is_same<T, Ts>...>::value) { cout << "disjunction" << endl; } } int main() { func(1, 2, 3); cout << "------ 1" << endl; func(1, "a"); cout << "------ 2" << endl; func(1, 2, "a"); cout << "------ 3" << endl; cout << negation<bool_constant<true>>::value << endl; cout << negation<bool_constant<false>>::value << endl; return 0; }
- 실행 결과
conjunction disjunction ------ 1 ------ 2 disjunction ------ 3 0 1